Amsterdam (Ohio)
Amsterdam sī Bí-kok Ohio chiu Jefferson kūn ê chi̍t ê chng-thâu (village).
Amsterdam | |
— Chng-thâu (village) — | |
Amsterdam só͘-chāi-tô͘ | |
Amsterdam tī Bí-kok Ohio ê ūi-tì | |
Keng-hūi-tō͘: 40°28′18″N 80°55′16″W / 40.47167°N 80.92111°W | |
Kok-ka | Bí-kok |
---|---|
Chiu | Ohio |
Kūn | Jefferson |
Chèng-hú | |
- Lūi-hêng | ''village'' |
Bīn-chek | |
- Lóng-chóng | 0.8 km2 |
Koân-tō͘ | 308 m |
Jîn-kháu | |
- Lóng-chóng | 553 lâng |
- Bi̍t-tō͘ | 691.3/km2 |
Jîn-kháu
Chit ūi tī 2010 nî ê jîn-kháu-sò͘ sī 511 lâng.
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