1824 United States presidential election in Indiana

The 1824 United States presidential election in Indiana took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

1824 United States presidential election in Indiana

← 1820October 26 – December 2, 18241828 →
 
NomineeAndrew JacksonHenry ClayJohn Quincy Adams
PartyDemocratic-RepublicanDemocratic-RepublicanDemocratic-Republican
Home stateTennesseeKentuckyMassachusetts
Running mateJohn C. CalhounNathan SanfordJohn C. Calhoun
Electoral vote500
Popular vote7,3435,3153,095
Percentage46.61%33.74%19.65%

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Indiana voted for Andrew Jackson over Henry Clay and John Quincy Adams. Jackson won Indiana by a margin of 12.87%.

Results

1824 United States presidential election in Indiana[1]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanAndrew Jackson7,34346.61%5
Democratic-RepublicanHenry Clay5,31533.74%0
Democratic-RepublicanJohn Quincy Adams3,09519.65%0
Totals15,753100.0%5

See also

References