1828 United States presidential election in Massachusetts

The 1828 United States presidential election in Massachusetts took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

1828 United States presidential election in Massachusetts

← 1824October 31 – December 2, 18281832 →
Turnout25.7%[1] Decrease 3.3 pp
 
NomineeJohn Quincy AdamsAndrew Jackson
PartyNational RepublicanDemocratic
Home stateMassachusettsTennessee
Running mateRichard RushJohn C. Calhoun
Electoral vote150
Popular vote29,8366,012
Percentage76.36%15.39%

County Results
Adams
  60-70%
  80-90%
  90-100%


President before election

John Quincy Adams
National Republican Party

Elected President

Andrew Jackson
Democratic Party

Massachusetts voted for the National Republican candidate, incumbent president John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Massachusetts by a landslide margin of 60.97%.

With 76.36% of the popular vote, Adams' home state would prove to be his second strongest victory in the 1828 election after neighboring Rhode Island.[2]

Results

1828 United States presidential election in Massachusetts[3]
PartyCandidateVotesPercentageElectoral votes
National RepublicanJohn Quincy Adams (incumbent)29,83676.36%15
DemocraticAndrew Jackson6,01215.39%0
N/AOther3,2268.26%0
Totals39,074100.0%15

See also

References