1832 United States presidential election in Alabama

The 1832 United States presidential election in Alabama took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose seven representatives, or electors, to the Electoral College, who voted for president and vice president.

1832 United States presidential election in Alabama

← 1828November 2 – December 5, 18321836 →
 
NomineeAndrew Jackson
PartyDemocratic
Home stateTennessee
Running mateMartin Van Buren
Electoral vote7
Popular vote14,286
Percentage99.97%

President before election

John Quincy Adams
Democratic-Republican

Elected President

Andrew Jackson
Democratic

Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Alabama by a margin of 99.94%.

Results

1832 United States presidential election in Alabama[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticAndrew Jackson (incumbent)14,28699.97%7
National RepublicanHenry Clay50.03%0
Totals14,291100.00%7

See also

References