1836 New Hampshire gubernatorial election

The 1836 New Hampshire gubernatorial election was held on 8 March 1836 in order to elect the Governor of New Hampshire. Former Democratic United States Senator from New Hampshire Isaac Hill defeated Whig nominee Joseph Healey and former Federalist Attorney General of New Hampshire George Sullivan.[1]

1836 New Hampshire gubernatorial election

← 18358 March 18361837 →
 
NomineeIsaac HillJoseph HealeyGeorge Sullivan
PartyDemocraticWhig
Popular vote24,9042,5662,230
Percentage81.22%8.37%7.27%

Governor before election

William Badger
Democratic

Elected Governor

Isaac Hill
Democratic

General election

On election day, 8 March 1836, Democratic nominee Isaac Hill won the election by a margin of 22,338 votes against his foremost opponent Whig nominee Joseph Healey, thereby retaining Democratic control over the office of Governor. Hill was sworn in as the 16th Governor of New Hampshire on 2 June 1836.[2]

Results

New Hampshire gubernatorial election, 1836
PartyCandidateVotes%
DemocraticIsaac Hill 24,904 81.22
WhigJoseph Healey2,5668.37
George Sullivan2,2307.27
Scattering9613.14
Total votes30,661 100.00
Democratic hold

References