1836 United States presidential election in Maryland

The 1836 United States presidential election in Maryland took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College,^[1] who voted for President and Vice President.

Maryland voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Maryland by a margin of 7.46%.

Results

1836 United States presidential election in Maryland^[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Whig	William Henry Harrison	25,852	53.73%	10
	Democratic	Martin Van Buren	22,267	46.27%	0
Totals			48,119	100.0%	10


County	William Henry Harrison Whig		Martin Van Buren Democratic		Margin		Total Votes Cast ^[3]
County	#	%	#	%	#	%	Total Votes Cast ^[3]
Allegany	926	56.77%	705	43.23%	221	13.55%	1631
Anne Arundel	1248	55.25%	1011	44.75%	237	10.49%	2259
Baltimore (City and County)	6699	44.89%	8222	55.11%	-1523	-10.22%	14,921
Calvert	363	56.11%	284	43.89%	79	12.21%	647
Caroline	576	53.93%	492	46.07%	84	7.87%	1068
Cecil	1020	48.30%	1092	51.70%	-72	-3.41%	2112
Charles	514	59.08%	356	40.92%	158	18.16%	870
Dorchester	966	58.19%	694	41.81%	272	16.39%	1660
Frederick	3130	50.94%	3015	49.06%	115	1.87%	6145
Harford	1080	54.00%	920	46.00%	160	8.00%	2000
Kent	589	61.61%	367	38.39%	222	23.22%	956
Montgomery	936	64.51%	515	35.49%	421	29.01%	1451
Prince George's	728	61.80%	450	38.20%	278	23.60%	1178
Queen Anne's	637	55.20%	517	44.80%	120	10.40%	1154
St. Mary's	643	77.19%	190	22.81%	453	54.38%	833
Somerset	1030	66.32%	523	33.68%	507	32.65%	1553
Talbot	656	57.80%	479	42.20%	177	15.59%	1135
Washington	2079	51.03%	1995	48.97%	84	2.06%	4074
Worcester	1032	65.61%	541	34.39%	491	31.21%	1573
Total	25852	53.73%	22267	46.27%	3585	7.46%	481119