The 1844 United States presidential election in Kentucky took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Kentucky voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won his home state by a margin of 8.18%.
With 54.09% of the popular vote, Clay's home state would be his third strongest victory after Rhode Island and Vermont.[1]
Results
| 1844 United States presidential election in Kentucky[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 61,249 | 54.09% | 12 | 100.00% | ||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 51,988 | 45.91% | 0 | 0.00% | ||
| Total | 113,237 | 100.00% | 12 | 100.00% | ||||
References
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