1856 United States presidential election in Georgia

The 1856 United States presidential election in Georgia took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

1856 United States presidential election in Georgia

← 1852November 4, 18561860 →
 
NomineeJames BuchananMillard Fillmore
PartyDemocraticKnow Nothing
Home statePennsylvaniaNew York
Running mateJohn C. BreckinridgeAndrew J. Donelson
Electoral vote100
Popular vote56,58142,439
Percentage57.14%42.86%

County Results

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

Georgia voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Georgia by a margin of 14.28%.

Republican Party candidate John C. Frémont was not on the ballot in the state.

Results

1856 United States presidential election in Georgia[1][2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
DemocraticJames Buchanan of PennsylvaniaJohn C. Breckinridge of Kentucky56,58157.14%10100.00%
Know NothingMillard Fillmore of New YorkAndrew Jackson Donelson of Tennessee42,43942.86%00.00%
Total99,020100.00%10100.00%

References


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