1856 United States presidential election in Kentucky

The 1856 United States presidential election in Kentucky took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for president and vice president.

1856 United States presidential election in Kentucky
← 1852November 4, 18561860 →
 
NomineeJames BuchananMillard Fillmore
PartyDemocraticKnow Nothing
Home statePennsylvaniaNew York
Running mateJohn C. BreckinridgeAndrew J. Donelson
Electoral vote120
Popular vote74,64267,416
Percentage52.54%47.46%

County Results

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

Kentucky voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Kentucky by a margin of 5.08%.

Republican Party candidate John C. Frémont was not on the ballot in the state.

Results

United States presidential election in Kentucky, 1856[1][2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
DemocraticJames Buchanan of PennsylvaniaJohn C. Breckinridge of Kentucky74,64252.54%12100.00%
Know NothingMillard Fillmore of New YorkAndrew Jackson Donelson of Tennessee67,41647.46%00.00%
Total142,058100.00%12100.00%

References


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