The 1876 Rhode Island gubernatorial election was held on April 5, 1876. Incumbent Republican Governor Henry Lippitt defeated Prohibition Party nominee Albert C. Howard and Democratic nominee William B. Beach.
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Since no candidate received a majority in the popular vote, Lippitt was elected by the Rhode Island General Assembly per the state constitution.
General election
Candidates
Major party candidates
- Henry Lippitt, Republican[1]
- William B. Beach, Democratic
Other candidates
- Albert C. Howard, Prohibition.[2][3][4][5] Howard was also supported by Republicans opposed to Lippitt.[6][7][a]
Results
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Republican | Henry Lippitt (incumbent) | 8,689 | 45.64% | ||
Prohibition | Albert C. Howard | 6,733 | 35.37% | ||
Democratic | William B. Beach | 3,599 | 18.91% | ||
Scattering | 16 | 0.08% | |||
Majority | 1,956 | 10.27% | |||
Turnout | 19,037 | ||||
Republican hold | Swing |
Legislative election
As no candidate received a majority of the vote, the Rhode Island General Assembly was required to decide the election, choosing among the top two vote-getters, Lippitt and Howard. The legislative election was held on May 30, 1876.
Party | Candidate | Votes | % | |
---|---|---|---|---|
Republican | Henry Lippitt | 74 | 71.84% | |
Prohibition | Albert C. Howard | 29 | 28.16% | |
Turnout | 103 |
Notes
References
Bibliography
- Kallenbach, Joseph E.; Kallenbach, Jessamine S., eds. (1977). American State Governors, 1776-1976. Vol. I. Dobbs Ferry, N.Y.: Oceana Publications, Inc. ISBN 0-379-00665-0.