1879 Rhode Island gubernatorial election

The 1879 Rhode Island gubernatorial election was held on April 2, 1879. Incumbent Republican Charles C. Van Zandt defeated Democratic nominee Thomas W. Segar with 62.09% of the vote.

1879 Rhode Island gubernatorial election

← 1878April 2, 18791880 →
 
NomineeCharles C. Van ZandtThomas W. Segar
PartyRepublicanDemocratic
Popular vote9,7175,506
Percentage62.09%35.18%

Governor before election

Charles C. Van Zandt
Republican

Elected Governor

Charles C. Van Zandt
Republican

General election

Candidates

Major party candidates

  • Charles C. Van Zandt, Republican
  • Thomas W. Segar, Democratic

Other candidates

  • Samuel Hill, Independent

Results

1879 Rhode Island gubernatorial election[1]
PartyCandidateVotes%±%
RepublicanCharles C. Van Zandt (incumbent) 9,717 62.09%
DemocraticThomas W. Segar5,50635.18%
GreenbackSamuel Hill3182.03%
Majority4,211
Turnout
Republican holdSwing

References