1936 United States presidential election in Delaware

The 1936 United States presidential election in Delaware was held on November 3, 1936. The state voters chose three electors to the Electoral College, who voted for president and vice president.

1936 United States presidential election in Delaware

← 1932 November 3, 1936 1940 →

Nominee Franklin D. Roosevelt Alf Landon Party Democratic Republican Home state New York Kansas Running mate John Nance Garner Frank Knox Electoral vote 3 0 Popular vote 69,702 57,236 Percentage 54.62% 44.85%

County Results Roosevelt   50-60%

President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

Delaware voted for Democratic Party candidate and incumbent President Franklin D. Roosevelt, who defeated Republican nominee, Kansas Governor Alf Landon. Roosevelt won the state by a margin of 9.77%, marking the first time since 1912 that the state voted for a Democratic presidential candidate, and the first time since 1888 that a Democrat carried the state with an outright majority.

While Landon lost the state, the 44.85% of the popular vote made Delaware his fifth strongest state in the 1936 election in terms of popular vote percentage after Vermont, Maine, New Hampshire and Kansas.^[1]

This election marked Delaware's transition into a bellwether state: for the rest of the 20th century, it would vote for a losing candidate only once (in 1948). Once the century rolled around, it came to be regarded as a solidly blue state.