1940 Iowa gubernatorial election

The 1940 Iowa gubernatorial election was held on November 5, 1940. Incumbent Republican George A. Wilson defeated Democratic nominee John K. Valentine with 52.72% of the vote.

1940 Iowa gubernatorial election

← 1938November 7, 19401942 →
 
NomineeGeorge A. WilsonJohn K. Valentine
PartyRepublicanDemocratic
Popular vote620,480553,941
Percentage52.72%47.07%

County results
Wilson:      40–50%      50–60%      60–70%
Valentine:      50–60%

Governor before election

George A. Wilson
Republican

Elected Governor

George A. Wilson
Republican

Primary elections

Primary elections were held on June 3, 1940.[1]

Democratic primary

Candidates

Results

Democratic primary results[1]
PartyCandidateVotes%
DemocraticJohn K. Valentine 70,233 57.88
DemocraticEdward Breen51,11242.12
Total votes121,345 100.00

Republican primary

Candidates

Results

Republican primary results[1]
PartyCandidateVotes%
RepublicanGeorge A. Wilson (incumbent) 165,176 49.66
RepublicanH. R. Gross146,39544.01
RepublicanIrving H. Knudson21,0396.33
Total votes332,610 100.00

General election

Candidates

Major party candidates

  • George A. Wilson, Republican
  • John K. Valentine, Democratic

Other candidates

  • M. M. Heptonstall, Prohibition
  • Charles Speck, Communist

Results

1940 Iowa gubernatorial election[2]
PartyCandidateVotes%±%
RepublicanGeorge A. Wilson (incumbent) 620,480 52.72%
DemocraticJohn K. Valentine553,94147.07%
ProhibitionM. M. Heptonstall1,2890.11%
CommunistCharles Speck1,2300.11%
Majority66,539
Turnout
Republican holdSwing

References