1948 Australian Championships – Women's singles

First-seeded Nancye Bolton defeated Marie Toomey 6–3, 6–1 in the final to win the women's singles tennis title at the 1948 Australian Championships.

Women's singles
1948 Australian Championships
Final
ChampionAustralia Nancye Bolton
Runner-upAustralia Marie Toomey
Score6–3, 6–1
Details
Draw28
Seeds8
Events
Singlesmenwomen
Doublesmenwomen
← 1947 ·Australian Championships· 1949 →

Seeds

The seeded players are listed below. Nancye Bolton is the champion; others show the round in which they were eliminated.

  1. Nancye Bolton (champion)
  2. Thelma Long (second round)
  3. Mary Bevis (semifinals)
  4. Marie Toomey (finalist)
  5. Pat Jones (second round)
  6. Nell Hopman (quarterfinals)
  7. Sadie Newcombe (second round)
  8. Dulcie Whittaker (first round)

Draw

Key

Finals

QuarterfinalsSemifinalsFinals
               
1 Nancye Bolton66
Joan Tuckfield20
1 Nancye Bolton66
3 Mary Beavis34
3 Mary Beavis76
6 Nell Hopman54
1 Nancye Bolton66
4 Marie Toomey31
Dorothy Jenkins63
4 Marie Toomey86
4 Marie Toomey476
Esme Ashford654
Esme Ashford66
Clare Proctor10

Earlier rounds

Section 1

First roundSecond roundQuarterfinalsSemifinals
1 Bolton66
Earle10
1 Bolton66
Martin Tuckfield20
8 Whittakerw/o Martin53
Tuckfield396 Tuckfield76
Thiele6741 Bolton66
3 Beavis663 Beavis34
Murphy223 Beavis66
McDermott66 McDermott24
Linehan003 Beavis76
6 Hopman666 Hopman54
Schultz006 Hopman66
Baker68 Baker13
Taylor46

Section 2

First roundSecond roundQuarterfinalsSemifinals
Jenkins66
Radford30 Jenkins366
5 Jones665 Jones634
Jackson02 Jenkins86
Moran664 Toomey63
Longton21 Moranw/o
4 Toomey664 Toomey
Griffiths004 Toomey476
Ashford646 Ashford654
Chamberlin262 Ashford647
7 Newcombe667 Newcombe065
Johnston10 Ashford66
Proctor10
Proctor
2 Longw/o

External links

  • [1] Source for the draw at ausopen.com
Preceded by Grand Slam women's singles Succeeded by