1847 Belgian general election

Partial general elections were held in Belgium on 8 June 1847.[1] The result was a victory for the new Liberal Association, which had been formed the previous year.[2] It won 33 seats to the Catholics' 21, as the latter were split into dogmatic and liberal groups.[2] Only 1% of the country's population was eligible to vote.[3]

1847 Belgian general election

← 18458 June 1847 (1847-06-08)1848 →

54 of the 108 seats in the Chamber of Representatives
55 seats needed for a majority
 First partySecond party
 
LeaderCharles RogierBarthélémy de Theux de Meylandt
PartyLiberalCatholic
Leader sinceCandidate for PMCandidate for PM
Seats won3321
Seats after5553
Popular vote9,1428,298
Percentage52.12%47.31%

Government before election

de Theux de Meylandt II
Catholic

Government after election

Rogier I
Liberal

Under the alternating system, Chamber elections were only held in four out of the nine provinces: East Flanders, Hainaut, Liège and Limburg. Thus, 54 of the 108 Chamber seats were up for election. The total number of Chamber seats increased from 98 to 108 following a reapportionment due to population increases.

While the liberals gained a majority in the Chamber, the Catholics retained theirs in the Senate. Following the election, the Catholic government led by Barthélémy de Theux de Meylandt resigned. After a political crisis of two months, a liberal government was formed on 12 August 1847, headed by Charles Rogier. The liberals would go on to win the 1848 elections.

Results

Chamber of Representatives

PartyVotes%Seats
WonTotal
Liberal Association9,14252.123355
Catholics8,29847.312153
Others1010.5800
Total17,541100.0054108
Total votes17,541
Registered voters/turnout22,57277.71
Source: Mackie & Rose

Senate

PartySeats+/–
Catholics320
Liberal Association20+7
Independents2–1
Total54+7
Source: Sternberger et al.

References