File:Hipocrat arcs.svg
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DescriptionHipocrat arcs.svg | Partial solution of the "Squaring the circle" task, suggested by Hipokrat. The area of the shaded figure is equal to the area of the triangle ABC. This is not a complete solution of the task (the complete solution is proven to be impossible). |
Date | 26 December 2005 (original upload date) |
Source | No machine-readable source provided. Own work assumed (based on copyright claims). |
Author | No machine-readable author provided. Audriusa assumed (based on copyright claims). |
Permission is granted to copy, distribute and/or modify this document under the terms of the GNU Free Documentation License, Version 1.2 or any later version published by the Free Software Foundation; with no Invariant Sections, no Front-Cover Texts, and no Back-Cover Texts. A copy of the license is included in the section entitled GNU Free Documentation License.http://www.gnu.org/copyleft/fdl.htmlGFDLGNU Free Documentation Licensetruetrue |
This file is licensed under the Creative Commons Attribution-Share Alike 3.0 Unported license. | ||
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This licensing tag was added to this file as part of the GFDL licensing update.http://creativecommons.org/licenses/by-sa/3.0/CC BY-SA 3.0Creative Commons Attribution-Share Alike 3.0truetrue |
Click on a date/time to view the file as it appeared at that time.
Date/Time | Thumbnail | Dimensions | User | Comment | |
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current | 11:15, 26 December 2005 | 500 × 500 (8 KB) | Audriusa | Partial solution of the "Squaring the circle" task, suggested by Hipokrat. The area of the shaded figure is equal to the area of the triangle ABC. This is not a complete solution of the task (the complete solution is proven to be inpossible). {{GFDL-self | |
11:11, 26 December 2005 | 500 × 500 (7 KB) | Audriusa | Partial solution of the "Squaring the circle" task, suggested by Hipokrat. The area of the shaded figure is equal to the area of the triangle ABC. This is not a complete solution of the task (the complete solution is proven to be inpossible). {{GFDL-self | ||
11:08, 26 December 2005 | 500 × 500 (7 KB) | Audriusa | Partial solution of the "Squaring the circle" task, suggested by Hipokrat. The area of the shaded figure is equal to the area of the triangle ABC. This is not a complete solution of the task (the complete solution is proven to be inpossible). {{GFDL-self |
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