1788–89 United States presidential election in Massachusetts

The 1788–89 United States presidential election in Massachusetts took place on January 7, 1789, as part of the 1788–1789 United States presidential election to elect the first President. Massachusetts was entitled to 10 electors, with two being appointed by the state legislature and the rest being chosen by state legislature from the two most popular candidates in each U.S. House district. Each elector voted once for President and again for Vice President.^[1]

1788–89 United States presidential election in Massachusetts

January 7, 1789 1792 →

Nominee George Washington John Adams Party Independent Federalist Home state Virginia Massachusetts Electoral vote 10 10 Popular vote 17,740 – Percentage 100.00% –

President before election Office established Elected President George Washington Independent

Massachusetts unanimously voted for independent candidate and commander-in-chief of the Continental Army, George Washington. The total vote is composed of 17,740 for Federalist electors, all of whom were supportive of Washington.