1792 United States presidential election in Massachusetts

The 1792 United States presidential election in Massachusetts took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. In this election, two Congressional districts chose five electors each, the remaining two districts chose three electors. Each elector chosen by majority vote of voters in Congressional district. If an insufficient number of electors are chosen by majority vote from a Congressional district, remaining electors would be appointed by the state legislature.^[1]

1792 United States presidential election in Massachusetts

← 1788–89 November 2 – December 5, 1792 1796 →

Nominee George Washington John Adams Party Independent Federalist Home state Virginia Massachusetts Electoral vote 16 16 Popular vote 20,343 – Percentage 100.00% –

President before election George Washington Independent Elected President George Washington Independent

Massachusetts unanimously voted for independent candidate and incumbent president, George Washington. The total vote is composed of 20,343 for Federalist electors, all of whom were supportive of Washington.^[2]