The 1868 United States presidential election in Iowa took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.
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Iowa voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 23.84%.
Results
| 1868 United States presidential election in Iowa[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Ulysses S. Grant of Illinois | Schuyler Colfax of Indiana | 120,399 | 61.92% | 8 | 100.00% | ||
| Democratic | Horatio Seymour of New York | Francis Preston Blair, Jr. of Missouri | 74,040 | 38.08% | 0 | 0.00% | ||
| Total | 194,439 | 100.00% | 8 | 100.00% | ||||