Mengde

Det miat för't mengde as Mol, det as en SI-grünjmiat. Uun ian Mol (n = 1) san amanbi 6,022 · 10²³ (Avogadro-taal) dialen.

${\displaystyle {\begin{aligned}n(X)\cdot N_{\mathrm {A} }&=N(X)\\\Leftrightarrow n(X)&={\frac {N(X)}{N_{\mathrm {A} }}}\end{aligned}}}$

mä mase

Bispal: Weeder wäächt 18 gram per Mol. Do san 9 gram weeder:

${\displaystyle n_{\mathrm {H_{2}O} }={\frac {m_{\mathrm {H_{2}O} }}{M_{\mathrm {H_{2}O} }}}=\mathrm {9\;g \over {18\;{g \over mol}}} =0{,}5\,\mathrm {mol} }$

mä woluumen

Bispal: Ian Mol faan en gas namt en rüm faan 22,4 liter iin. Hüföl Mol san 5 l sürstoof?

${\displaystyle n_{\mathrm {O_{2}} }={V_{\mathrm {O_{2}} } \over {V_{\mathrm {m} }}}={{5\,\mathrm {l} } \over {22{,}4{\mathrm {l \over mol} }}}=0{,}22\,\mathrm {mol} }$

mä taal faan dialen

Bispal: Dü heest N = 10²⁵ elementaardialen.

${\displaystyle n={\frac {N}{N_{\mathrm {A} }}}={\frac {10^{25}}{6{,}022\cdot 10^{23}\;\mathrm {mol} ^{-1}}}=16{,}606\;\mathrm {mol} }$

mä konsentratjuun

Bispal: Hüföl Mol Natriumchlorid san uun 0,22 liter faan en 0,6-molaar NaCl-liasang?

${\displaystyle n_{\mathrm {NaCl} }=c_{\mathrm {NaCl} }\cdot V=0{,}6\;{\frac {\mathrm {mol} }{\mathrm {l} }}\cdot 0{,}22\;\mathrm {l} =0{,}132\;\mathrm {mol} }$